Answer
$e^{\sin\theta} +C$
Work Step by Step
Let $u=\sin \theta$. Then $du=\cos\theta\ d\theta$.
$\int e^{\sin\theta}\cos\theta\ d\theta$
$=\int e^u du$
$=e^u+C$
$=e^{\sin\theta} +C$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 6 - Inverse Functions - 6.3* The Natural Exponential Function - 6.3* Exercises - Page 454: 92
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