Answer
$\frac{(4+e^x)^6}{6}+C$
Work Step by Step
Let $u=4+e^x$. Then $du=e^xdx$.
$\int e^x(4+e^x)^5 dx$
$=\int (4+e^x)^5e^x dx$
$=\int u^5 du$
$=\frac{u^6}{6}+C$
$=\frac{(4+e^x)^6}{6}+C$
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