## Calculus 8th Edition

$lnb+2lnc-3lnd=ln[\frac{bc^{2}}{d^{3}}]$
To express the quantity as a single quantity we need to follow some steps. 1.Use logarithmic properties $ln(pq) = lnp+lnq$ and $ln(p)^{m}= m lnp$. $lnb+2lnc-3lnd=lnb+lnc^{2}-lnd^{3}$ $= ln(bc^{2})-ln(d^{3})$ $=ln[\frac{bc^{2}}{d^{3}}]$ Hence, $lnb+2lnc-3lnd=ln[\frac{bc^{2}}{d^{3}}]$