Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.2* The Natural Logarithmic Functions - 6.2* Exercises - Page 445: 1


ln$\sqrt ab=\frac{1}{2}(lna+lnb)$

Work Step by Step

Use logarithmic properties $ln(pq) = lnp+lnq$ and $ln(p)^{m}= m lnp$ Consider the quantity $ln\sqrt ab$ as follows: ln$\sqrt ab=ln(ab)^{\frac{1}{2}}$ This implies ln$\sqrt ab=\frac{1}{2}ln(ab)$ ln$\sqrt ab=\frac{1}{2}(lna+lnb)$
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