## Calculus 8th Edition

ln$\sqrt ab=\frac{1}{2}(lna+lnb)$
Use logarithmic properties $ln(pq) = lnp+lnq$ and $ln(p)^{m}= m lnp$ Consider the quantity $ln\sqrt ab$ as follows: ln$\sqrt ab=ln(ab)^{\frac{1}{2}}$ This implies ln$\sqrt ab=\frac{1}{2}ln(ab)$ ln$\sqrt ab=\frac{1}{2}(lna+lnb)$