Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.1 Inverse Functions - 6.1 Exercises - Page 406: 2



Work Step by Step

$y$$=$$e$$^x$ is the top function $y=xe^{(x^2)}$ is the bottom function they meet at x = 0 and x = 1 so the equation to solve is: $\int$$e^xdx-$$\int$$xe^{(x^2)}$ evaluated from 0 to 1 evaluate first integral, use U substitution for second integral where $u=x^2$ and $du=2x$ $e$$^x$ $-$ $1/2$$\int$$e$$^u$$du$ evaluated from 0 to 1 $(e^1-e^0)-1/2(e^1-e^0)$ $1/2(e^1)$ plug in $e^1$ $\frac{1.718}{2}$
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