## Calculus 8th Edition

$\frac{1.718}{2}$
$y$$=$$e$$^x is the top function y=xe^{(x^2)} is the bottom function they meet at x = 0 and x = 1 so the equation to solve is: \int$$e^xdx-$$\int$$xe^{(x^2)}$ evaluated from 0 to 1 evaluate first integral, use U substitution for second integral where $u=x^2$ and $du=2x$ $e$$^x - 1/2$$\int$$e$$^u$$du$ evaluated from 0 to 1 $(e^1-e^0)-1/2(e^1-e^0)$ $1/2(e^1)$ plug in $e^1$ $\frac{1.718}{2}$