Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.1 Inverse Functions - 6.1 Exercises: 11


This function is not one to one.

Work Step by Step

Let $y=g(x)=1-\sin x$. This function is not one-to-one because $y=1$ for every $x$ of the form of $x=k\pi$, where $k$ is integer because $\sin k\pi=0$. This means that to the same value of the function correspond multiple values of the argument so the function is not one-to-one.
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