Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 4 - Integrals - Review - Exercises - Page 350: 26


$$-\sin (\cos x)+c$$

Work Step by Step

Given $$\int \sin x\cos (\cos x)dx $$ Let $u=\cos x\ \Rightarrow \ du -\sin x dx$ \begin{align*} \int \sin x\cos (\cos x)dx&=-\int \cos (u)du\\ &=-\sin u+c\\ &=-\sin (\cos x)+c \end{align*}
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