Answer
$$-\sin (\cos x)+c$$
Work Step by Step
Given
$$\int \sin x\cos (\cos x)dx $$
Let $u=\cos x\ \Rightarrow \ du -\sin x dx$
\begin{align*}
\int \sin x\cos (\cos x)dx&=-\int \cos (u)du\\
&=-\sin u+c\\
&=-\sin (\cos x)+c
\end{align*}
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 4 - Integrals - Review - Exercises - Page 350: 26
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