Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 3 - Applications of Differentiation - 3.4 Limits at Infinity; Horizontal Asymptotes - 3.4 Exercises - Page 242: 26



Work Step by Step

Given $$\lim _{x \rightarrow \infty}\sqrt{ x^2+1}$$ Then \begin{aligned} \lim _{x \rightarrow \infty}\sqrt{ x^2+1}&=\sqrt{\lim _{x \rightarrow \infty} (x^2+1)}\\ &=\sqrt{ \infty}\\ &=\infty \end{aligned}
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