Answer
Because f(0)$\lt$0 and f(1)$\gt$0, there exists a value "c" such that f(c) = 0 on the interval.
Work Step by Step
Firstly, set the equation equal to zero.
0=$e^{x}$+2x-3
The given set of points, (0,1) tells us which values of x we are going to plug in.
Solve for f(0) and f(1),
f(0)= -2 = negative number
f(1) = positive number
Therefore, because f(0)$\lt$0 and f(1)$\gt$0, there exists a value "c" such that f(c) = 0 on the interval.
