#### Answer

$$f'(t)=\sin\pi t+\pi t\cos\pi t$$

#### Work Step by Step

$$f'(t)=(t\sin \pi t)'=t'\cdot\sin\pi t+t\cdot(\sin\pi t)'=
1\cdot\sin\pi t+t\cdot\cos\pi t(\pi t)'=
\sin\pi t+t\cos\pi t\cdot\pi=\sin\pi t+\pi t\cos\pi t$$

Published by
Cengage

ISBN 10:
1285740629

ISBN 13:
978-1-28574-062-1

$$f'(t)=\sin\pi t+\pi t\cos\pi t$$

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.