Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.5 The Chain Rule - 2.5 Exercises - Page 158: 13


$f'(θ)= -2θsin(θ^2)$

Work Step by Step

Original Expression: $f(θ) = cos(θ^2) $ $u=θ^2$ $f(u)= cos(u)$ Apply the chain rule: $f'(u)u'$ $f'(u)= -sin(u)2θ$ $f'(θ)= -2θsin(θ^2)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.