Answer
$y$ = $-2x+3$
Work Step by Step
$y$ = $\sqrt x$
$m$ = $y'$ = $\frac{1}{2\sqrt x}$
$2x+y$ = $1$
$y$ = $-2x+1$
$m$ = $-2$
the tangent line to the curve have slope $\frac{1}{2}$
so
$\frac{1}{2\sqrt x}$ = $\frac{1}{2}$
$x$ = $1$
$y$ = $\sqrt x$ = $\sqrt {1}$ = $1$
the equation of the normal line is
$y-1$ = $-2(x-1)$
$y$ = $-2x+3$
