Answer
$=4e^{2}-4e+3$
Work Step by Step
$\int_{1}^{2}\int_{0}^{2}(y+2xe^{y})dxdy=\int_{1}^{2}(xy+x^{2}e^{y})|_{0}^{2}dy$
$=\int_{1}^{2}(2y+4e^{y})dy$
$=(y^{2}+4e^{y})|_{1}^{2}$
$=4e^{2}-4e+3$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 15 - Multiple Integrals - Review - Exercises - Page 1102: 3
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