Answer
$e-2$
Work Step by Step
$\int_{0}^{1}\int_{0}^{1}ye^{xy}dxdy=\int_{1}^{2}e^{xy})|_{0}^{1}dy$
$=\int_{0}^{1}e^{y}-1dy$
$=e^{y}-y|_{0}^{1}$
$=e-2$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 15 - Multiple Integrals - Review - Exercises - Page 1102: 4
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