Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 15 - Multiple Integrals - Review - Exercises - Page 1102: 25



Work Step by Step

$\int\int_{D}ydA=\int_{0}^{2}\int_{y^{2}} ^{8-y^{2}} ydxdy$ $=\int_{0}^{2} [y(8-y^{2}-y^{2})]dy$ $=\int_{0}^{2} [8y-y^{3}]dy$ $=[\frac{8y^{2}}{2}-\frac{2y^{4}}{4}]_{0}^{2}$ $=16-8$ $=8$
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