Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 13 - Vector Functions - 13.3 Arc Length and Curvature - 13.3 Exercises - Page 908: 7

Answer

$18.6833$

Work Step by Step

Length of the curve can be obtained by using formula, such as $L=\int_a^b |r'(t)| dt$ Now, $r'(t)=\lt 2t,3t^2,4t^3\gt$ ;$|r'(t)|=\sqrt {( 2t)^2+(3t^2)^2+(4t^3)^2}dt$ or, $=\sqrt{ 4t^2+9t^4+16t^6}$ Since, $L=\int_{0}^2(\sqrt{ 4t^2+9t^4+16t^6}) dt= 18.6833$ The above result is calculated with the help of a calculator.
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