Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 13 - Vector Functions - 13.3 Arc Length and Curvature - 13.3 Exercises - Page 908: 24

Answer

$\dfrac{\sqrt{30}}{18}$

Work Step by Step

As we are given that $r(t)=\lt t^2, \ln t, t \ln t \gt$ Write Theorem 10. $\dfrac{|r'(t) \times r''(t)|}{|r'(t)|^3}$ Solve $r'(t)=\lt 2t, \frac{1}{t}, \ln t +1 \gt$; $r''(t)=\lt 2, -\frac{1}{t^2}, \frac{1}{t} \gt$ Thus, $\dfrac{|r'(t) \times r''(t)|}{|r'(t)|^3}=\dfrac{|\frac{1}{t^2}(2+\ln t)i+2 \ln t j4/tk^ |}{[4t^2+\frac{1}{t^2}+ (\ln t+1)^2]^{3/2}}$ From the question, we have $(1,0,0)$ $\dfrac{|r'(t) \times r''(t)|}{|r'(t)|^3}=\dfrac{|2 i+0 j-4k |}{[6]^{3/2}}$ $=\dfrac{\sqrt{30}}{18}$ This is the desired result.
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