## Calculus 8th Edition

$r= \frac{6}{1 + sin (θ)}$
$r= \frac{ed}{1 + e sin (θ)}$ (sine since directrix is vertical line) e = 1 since it is a parabola, vertedx is at (3, $\pi /2$) $r= \frac{d}{1 + sin (θ)}$ Substitute (3, $\pi /2$) into the equation $3= \frac{d}{1 + sin (\pi /2) }$ $3= \frac{d}{2}$ Thus d=6 $r= \frac{6}{1 + sin (θ)}$