## Calculus 8th Edition

Published by Cengage

# Chapter 10 - Parametric Equations and Polar Coordinates - 10.6 Conic Sections in Polar Coordinates - 10.6 Exercise - Page 728: 1

#### Answer

$r= \frac{4}{2 + cos(θ)}$

#### Work Step by Step

$r= \frac{ed}{1 + e cos(θ)}$ e = 1/2, directrix (d) = 4 $r= \frac{(1/2) (4)}{1 + (1/2) cos(θ)}$ $r= \frac{2}{1 + 0.5 cos(θ)}$ $r= \frac{4}{2 + cos(θ)}$

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