Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - 10.6 Conic Sections in Polar Coordinates - 10.6 Exercise - Page 728: 3

Answer

$r= \frac{6}{2 - 3 sin(θ)}$

Work Step by Step

$r= \frac{ed}{1 + e sin (θ)}$ (sine since directrix is horizontal line) e = 1.5, directrix is at y=2. Focus is at (0,0) so d= 2, $r= \frac{(1.5) (2)}{1 + (1.5) sin(θ)}$ $r= \frac{3}{1 + 3 sin(θ)}$ $r= \frac{6}{2 + 3 sin(θ)}$
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