Answer
$$A=(\frac{3\pi}{2}-4)$$
Work Step by Step
$$A=\int_{0}^{\pi/2}\frac{(1-cos\theta)^{2}}{2}d \theta=\int_{0}^{\pi/2}\frac{(1-2cos\theta+cos^{2}\theta)}{2}d \theta$$
Or,
$$=\frac{1}{4}[3\theta-4sin\theta+\frac{1}{2}sin2\theta]_{0}^{\pi/2}$$
Hence, $$A=(\frac{3\pi}{2}-4)$$