Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - 10.4 Areas and Lengths in Polar Coordinates - 10.4 Exercises - Page 713: 27

Answer

$$A =\pi$$

Work Step by Step

$$A=\frac{1}{2}\int_{0}^{\pi/3}(3cos\theta)^{2}d \theta-\frac{1}{2}\int_{0}^{\pi/3}(1+cos\theta)^{2}d \theta=\frac{1}{2}[3\theta+2sin2\theta-2sin\theta]_{0}^{\pi/3}$$ Or, $$A=\frac{\pi}{2}$$ Since, the area of the whole crescent is calculated as $$2 \cdot(\frac{\pi}{2})$$ Hence, $$A =\pi$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.