Answer
a. See the graph
b. $y=1-x^{2}$, $x\geq 0$
Work Step by Step
a. Using the given equations, $x=\sqrt{t}$ and $y=1-t$ create a table of values in terms of $x$ and $y$, using values of $t$ within the given interval ($t\geq 0$). Then, plot the calculated points from the lowest $t$ value to the highest $t$ value. This will give the direction of the curve.
b. $x=\sqrt{t}$
$t=x^{2}$ .....(1)
$y=1-t$ ....(2)
by substituting 2 into 1 we get:
$y=1-x^{2}$
Since $t$\geq 0, $x \geq 0$.
So the curve is the right half of the parabola $y = 1 − x^{2}$
