## Calculus 8th Edition

$$y=(x-2)^{2}+1$$
Given $$y=x^{2}-4 x+5$$ \begin{align} y&=x^{2}-4 x+5\\ &=\left(x^{2}-4 x+4\right)+1\\ &=(x-2)^{2}+1 \end{align} begin with the graph of $y=x^{2}$ in Fig.(1), shift $2$ units to the right in Fig.(2), and then shift upward $1$ unit in Fig(3).