Answer
4
Work Step by Step
$\lim\limits_{x \to 5} \frac{x^2 - 6x + 5}{x -5} = \lim\limits_{x \to 5} \frac{(x - 5)(x-1)}{x -5} = \lim\limits_{x \to 5} x - 1 = 4$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 1 - Functions and Limits - 1.5 The Limit of a Function - 1.5 Exercises - Page 60: 11
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