Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - 1.3 New Functions from Old Functions - 1.3 Exercises: 55

Answer

(a)$$r=60t$$ (b)$$A= 3600 \pi t^2$$ This function represents the area of growing ripple in terms of time.

Work Step by Step

(a) The value of the increasing radius equals the velocity times the elapsed time. So we have $$r=v \times t=60t.$$ (b) $$A= \pi r^2 \quad \Rightarrow$$ $$(A \circ r)(t)=A(r(t))=3600 \pi t^2$$
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