#### Answer

$(f\circ g\circ h) (x)=|2^{\sqrt{x}}-4|$

#### Work Step by Step

$(f\circ g\circ h) (x)=f[g(h(x))]$
$g(h(x))=2^{h(x)}=2^{\sqrt{x}}$
$f[g(h(x))]=f(2^{\sqrt{x}})=|2^{\sqrt{x}}-4|$

Published by
Cengage

ISBN 10:
1285740629

ISBN 13:
978-1-28574-062-1

$(f\circ g\circ h) (x)=|2^{\sqrt{x}}-4|$

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