#### Answer

$(f\circ g\circ h) (x)=\displaystyle \tan(\frac{\sqrt[3]{x}}{\sqrt[3]{x}-1})$

#### Work Step by Step

$(f\circ g\circ h) (x)=f[g(h(x))]$
$g(h(x))=g(\displaystyle \sqrt[3]{x})=\frac{\sqrt[3]{x}}{\sqrt[3]{x}-1}$
$f[g(h(x))]=f(\displaystyle \frac{\sqrt[3]{x}}{\sqrt[3]{x}-1})=\tan(\frac{\sqrt[3]{x}}{\sqrt[3]{x}-1})$