Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Appendix C - Graphs of Second-Degree Equations - C Exercises: 7

Answer

center,$(h,k)=(-\frac{1}{2},0)$ and $r= \frac{1}{2}$

Work Step by Step

An equation of the circle with center $(h,k)$ and radius $r$ is given as: $(x-h)^{2}+(y-k)^{2}=r^{2}$ ...(1) Given: $x^{2}+ y^{2}+x = 0$ The above equation can be written in the standard equation of the circle as follows: $(x-(-\frac{1}{2}))^{2}+ (y-0)^{2} = (\frac{1}{2})^{2}$ Compare it with equation (1), we have Hence, center,$(h,k)=(-\frac{1}{2},0)$ and $r= \frac{1}{2}$
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