Answer
$(x+1)^{2}+(y-5)^{2}=130$
Work Step by Step
An equation of the circle with center $(h,k)$ and
radius $r$ is given as:
$(x-h)^{2}+(y-k)^{2}=r^{2}$
Given: center,$(h,k)=(-1,5)$ and $(x,y)=(-4-6)$
Then
$(-4+1)^{2}+(-6-5)^{2}=r^{2}$
$r^{2}=130$
Hence, $(x+1)^{2}+(y-5)^{2}=130$
