Answer
The integral does not converge
Work Step by Step
$\int_0^R{secθ}dθ$ = $\ln|secθ+tanθ||_0^R$ = $\ln|secR+tanR|$
$\int_0^{\frac{\pi}{2}}{secθ}dθ$ = $\lim\limits_{R \to {\frac{\pi}{2}}^{-}}$$\int_0^R{secθ}dθ$ = $\infty$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 8 - Techniques of Integration - 8.7 Improper Integrals - Exercises - Page 440: 34
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