Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.9 Hyperbolic Functions - Exercises - Page 384: 10


$$ y'= 2x \cosh (x^2)$$

Work Step by Step

Since $ y=\sinh (x^2)$, then using the chain rule, the derivative $ y'$ is given by $$ y'= \cosh (x^2) (x^2)'=2x \cosh (x^2).$$
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