$$\int \sinh (x+1) dx= \cosh (x+1)+c.$$
Work Step by Step
Let $ u=x+1$, then $ du=dx $ and hence $$\int \sinh (x+1) dx= \int \sinh udu = \cosh u+c \\= \cosh (x+1)+c.$$
You can help us out by revising, improving and updating this answer.Update this answer
After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.