Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.9 Hyperbolic Functions - Exercises - Page 384: 36


$$\int \sinh (x+1) dx= \cosh (x+1)+c.$$

Work Step by Step

Let $ u=x+1$, then $ du=dx $ and hence $$\int \sinh (x+1) dx= \int \sinh udu = \cosh u+c \\= \cosh (x+1)+c.$$
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