Answer
$$ f(t)=9 e^{1.4 t}=9 (e^{1.4 })^t=P_0 b^t $$
where, $ P_0=9$ and $ b=e^{1.4}$.
Work Step by Step
Using the property that $ e^{xy}=(e^{x})^y $, we have
$$ f(t)=9 e^{1.4 t}=9 (e^{1.4 })^t=P_0 b^t $$
where, $ P_0=9$ and $ b=e^{1.4}$.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.4 Exponential Growth and Decay - Exercises - Page 349: 4
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