## Calculus (3rd Edition)

$$f(t)=9 e^{1.4 t}=9 (e^{1.4 })^t=P_0 b^t$$ where, $P_0=9$ and $b=e^{1.4}$.
Using the property that $e^{xy}=(e^{x})^y$, we have $$f(t)=9 e^{1.4 t}=9 (e^{1.4 })^t=P_0 b^t$$ where, $P_0=9$ and $b=e^{1.4}$.