## Calculus (3rd Edition)

(a) $$P(0)= 2000.$$ (b) $$t=\frac{\ln5}{1.3}.$$
(a) The number is given at $t=0$, so we have $$P(0)=2000e^0=2000.$$ (b) We have $$10.000=2000e^{1.3t}\Longrightarrow 1.3t=\ln 5\Longrightarrow t=\frac{\ln5}{1.3}.$$