Answer
(a) $ t=\frac{\ln10}{5}$
(b) $ \frac{\ln 2}{5}$
Work Step by Step
(a) We have
$$10=e^{5t}\\
5t=\ln 10\\
t=\frac{\ln10}{5}$$
(b) The doubling time for $ P $ is given by $\frac{\ln 2}{k}=\frac{\ln 2}{5}$.
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