## Calculus (3rd Edition)

$98,000 \ J$
The force required to lift the container is equal to: $(9.8) [20+(100-0.4 y)] =(1176 - 3.92 y ) \ N$ Therefore, the work done to lift the container can be computed as: $W= \int_{0}^{100} (1176-3.92 y) \ d y\\= (1176 y-1.96 y^2)_{0}^{100} \\=(1176)(100) -(1.96)(10000) \\= 98,000 \ J$