#### Answer

$98,000 \ J$

#### Work Step by Step

The force required to lift the container is equal to:
$ (9.8) [20+(100-0.4 y)] =(1176 - 3.92 y ) \ N$
Therefore, the work done to lift the container can be computed as:
$ W= \int_{0}^{100} (1176-3.92 y) \ d y\\= (1176 y-1.96 y^2)_{0}^{100} \\=(1176)(100) -(1.96)(10000) \\= 98,000 \ J$