## Calculus (3rd Edition)

$1.08 \ J$
The work required to compress the spring beyond equilibrium can be calculated as: $\text{Work}, W= \int_{m}^{n} kx \ dx$; where $k$ is the spring constant. and $\dfrac{1}{2} k(0.2)^2=12 \implies k =600 \ N/m$ Now, $W= \int_{m}^{n} kx \ dx\\= \int_{0}^{0.06} 600 \ x \ dx\\=600 [\dfrac{x^2}{2}]_{0}^{0.06} \\=(600) \times [\dfrac{(0.06)^2}{2}] \\=1.08 \ J$