Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 6 - Applications of the Integral - Chapter Review Exercises - Page 320: 45

Answer

a) $A$ = $\int_0^1[\sqrt {1-(x-1)^{2}}-(1-\sqrt {1-x^{2}})]dx$ b) $V$ = ${\pi}\int_0^1[({1-(x-1)^{2}})-(1-\sqrt {1-x^{2}})^{2}]dx$

Work Step by Step

a) $A$ = $\int_0^1[\sqrt {1-(x-1)^{2}}-(1-\sqrt {1-x^{2}})]dx$ b) $V$ = ${\pi}\int_0^1[({1-(x-1)^{2}})-(1-\sqrt {1-x^{2}})^{2}]dx$
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