Answer
$24$
Work Step by Step
The area $(A)$ can be calculated as:
$A=\int_{0}^2 [24-8y-4y] \ dy \\= \int_0^2 [24y-12y] \\=[ 24 y -\dfrac{12 y^2}{2} ]_0^2 \\=[24y-6y^2]_0^2 \\= 48-24 \\=24$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 6 - Applications of the Integral - Chapter Review Exercises - Page 319: 5
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