Chapter 6 - Applications of the Integral - Chapter Review Exercises - Page 319: 16

$16$

Work Step by Step

The volume of a solid can be calculated as: $Volume, V= \int_{0}^{4} (y+2) \ dy \\=[\dfrac{y^2}{2} +2y]_0^4 \\=\dfrac{(4^2)}{2} +2(4) \\=[\dfrac{16}{2} +8] \\=8+8 \\=16$

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