Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 6 - Applications of the Integral - Chapter Review Exercises - Page 319: 29

Answer

$\dfrac{162 \pi}{5}$

Work Step by Step

The volume of a solid by using the washer method can be calculated as: $V=\pi \int_{m}^{n} (R^2_{outer}-r^2_{inner}) \ dx \\=\pi \int_{-1}^{2} [(x+4)^2-(x^2+2)^2] \ dx \\=\pi \int_{-1}^{2} (8x-x^4-3x^2+12) \ dx \\=\pi [4x^2 -\dfrac{1}{5} x^5 -x^3 +12 x ]_{-1}^2 \\=\pi [\dfrac{128}{5}+\dfrac{34}{5}] \\=\dfrac{162 \pi}{5}$
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