Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 6 - Applications of the Integral - 6.1 Area Between Two Curves - Exercises - Page 286: 5


$A=\sqrt 2-1$

Work Step by Step

$A=\int_{\frac{\pi}{4}}^{\frac{\pi}{2}}(sin(x)-cos(x))dx$ $A=[-cos(x)-sin(x)]_{\frac{\pi}{4}}^{\frac{\pi}{2}}$ $A=[0-1]-[-\frac{1}{\sqrt 2}-\frac{1}{\sqrt 2}]$ $A=\sqrt 2-1$
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