## Calculus (3rd Edition)

$128$
$\int_0^4 6x - x^3 + 10xdx$ $= [3x^2 - \frac{1}{4}x^4 + 5x^2]_0^4$ $48 - 64 + 80 = 64$ Since the graph is symmetric, we can just multiply our answer by 2 for the other half. $64 * 2 = 128$