Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 6 - Applications of the Integral - 6.1 Area Between Two Curves - Exercises - Page 286: 4

Answer

$128$

Work Step by Step

$\int_0^4 6x - x^3 + 10xdx$ $= [3x^2 - \frac{1}{4}x^4 + 5x^2]_0^4$ $48 - 64 + 80 = 64$ Since the graph is symmetric, we can just multiply our answer by 2 for the other half. $64 * 2 = 128$
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