Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.2 The Definite Integral - Exercises - Page 245: 38



Work Step by Step

$\int^{1/2}_{0}(12y^{2}+6y)dy$ $=12\int^{1/2}_{0}y^{2}dy+6\int^{1/2}_{0}ydy$ $=12\times\frac{(\frac{1}{2})^{3}}{3}+6\times\frac{(\frac{1}{2})^{2}}{2}$ $=12\times\frac{1}{24}+6\times\frac{1}{8}$ $=\frac{5}{4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.