Answer
a) $-\frac{\pi}{2}$
b) $\frac{3\pi}{2}$
Work Step by Step
a)
$\int_0^2f(x)dx$ = $-\frac{1}{2}\pi(1)^{2}$ = $-\frac{\pi}{2}$
b)
$\int_0^6f(x)dx$ = $\frac{1}{2}\pi(2)^{2}-\frac{1}{2}\pi(1)^{2}$ = $2\pi-\frac{\pi}{2}$ = $\frac{3\pi}{2}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.2 The Definite Integral - Exercises - Page 245: 13
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