Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.2 The Definite Integral - Exercises - Page 245: 36



Work Step by Step

We know that $\int^{b}_{a}x^{2}dx=\frac{b^{3}}{3}-\frac{a^{3}}{3}$ Then $\int^{5}_{2}x^{2}dx= \frac{5^{3}}{3}-\frac{2^{3}}{3}$ $=\frac{125}{3}-\frac{8}{3}= \frac{117}{3}=39$
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