## Calculus (3rd Edition)

We know that $\int^{b}_{a}x^{2}dx=\frac{b^{3}}{3}-\frac{a^{3}}{3}$ Then $\int^{5}_{2}x^{2}dx= \frac{5^{3}}{3}-\frac{2^{3}}{3}$ $=\frac{125}{3}-\frac{8}{3}= \frac{117}{3}=39$