Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.1 Approximating and Computing Area - Exercises - Page 235: 25

Answer

$$\sum_{i=2}^{5} (2^i+2)$$

Work Step by Step

Given $$\left(2^{2}+2\right)+\left(2^{3}+2\right)+\left(2^{4}+2\right)+\left(2^{5}+2\right)$$ The first term is $ \left(2^{2}+2\right)$, the last term is $\left(2^{5}+2\right)$, and the power is increasing by $1$, so $$\left(2^{2}+2\right)+\left(2^{3}+2\right)+\left(2^{4}+2\right)+\left(2^{5}+2\right)=\sum_{i=2}^{5} (2^i+2)$$
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