Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.1 Approximating and Computing Area - Exercises - Page 235: 25


$$\sum_{i=2}^{5} (2^i+2)$$

Work Step by Step

Given $$\left(2^{2}+2\right)+\left(2^{3}+2\right)+\left(2^{4}+2\right)+\left(2^{5}+2\right)$$ The first term is $ \left(2^{2}+2\right)$, the last term is $\left(2^{5}+2\right)$, and the power is increasing by $1$, so $$\left(2^{2}+2\right)+\left(2^{3}+2\right)+\left(2^{4}+2\right)+\left(2^{5}+2\right)=\sum_{i=2}^{5} (2^i+2)$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.