Answer
$$\sum_{i=4}^{8}i^7 $$
Work Step by Step
Given $$ 4^{7}+5^{7}+6^{7}+7^{7}+8^{7}$$
Since every term has the same power of $7$ and we begin with $4$, with increments of $1$, then
$$4^{7}+5^{7}+6^{7}+7^{7}+8^{7}=\sum_{i=4}^{8}i^7 $$
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