## Calculus (3rd Edition)

$$\sum_{i=4}^{8}i^7$$
Given $$4^{7}+5^{7}+6^{7}+7^{7}+8^{7}$$ Since every term has the same power of $7$ and we begin with $4$, with increments of $1$, then $$4^{7}+5^{7}+6^{7}+7^{7}+8^{7}=\sum_{i=4}^{8}i^7$$