# Chapter 3 - Differentiation - Chapter Review Exercises - Page 164: 72

$$\frac{dy}{dx}=\frac{y+2x}{1-x}, \quad x\neq 1.$$

#### Work Step by Step

Simplify the given equation first by multiplying both sides by $x$; We then have $y=x^2+xy$. Now, by differentiating the equation $y=x^2+xy$ with respect to $x$, we get $$\frac{dy}{dx}=2x+y+x \frac{dy}{dx}\Longrightarrow \frac{dy}{dx}(1-x)=y+2x$$ and hence $$\frac{dy}{dx}=\frac{y+2x}{1-x}, \quad x\neq 1.$$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.